/*
 * To compute the avarage of the elements of an array using pointers
 * @author-Karan Narain(karan@iitk.ac.in)
 *
*/
#include <stdio.h>
void avg(int *p)
{
	int *q,sum=0,rounded_avg,i=0;
	float av;
	q=p+1;
	while(*q!=0)
	{
		sum=sum + *q;
		i++;
		q++;
	}
	av=((float)sum)/i;
	rounded_avg=av; 	//here,rounded_avg would hold the integer(truncated) value of av
	if(av-rounded_avg>=0.5)	//if decimal part is >=0.5
	rounded_avg=rounded_avg+1;
	//store the average in A[0] using p (as p points to A[0])
	*p=rounded_avg;
	printf("\nThe rounded average is %d\n",*p);
	return;

}

int main()
{
	int A[10],i=1,temp,len,*p=NULL;

	//len holds the number of elements in array A.It would be equal to the last value of i before the while loop ends or breaks
	while(i<10)
	{
		printf("Enter a positive element(To stop entering,enter a zero)\n");
		scanf("%d",&temp);
		if(temp==0)
		{
			A[i]=temp;
			break;
		}
		else if(temp<0)
		continue;	//continue will take the control back to while(i<10) for a new iteration,i.e. another element will be input
		else
		{
			A[i]=temp;
			i++;
		}
	
	}
	len=i;
	//if no element was entered
	if(len==1)
	printf("The array has no elements\n");
	else
	{
	printf("The array you entered is :\n");
	for(i=1;i<len;i++)
	printf("%d ",A[i]);
	//Make pointer p point to the first element of the array A
	p=&A[0];
	avg(p);
	}
	return 0;

}