/*
 *Input 10 numbers and output the number of closest to the average.  If two
 *numbers are equally close, output the larger one.
 *author:rahule@cse.iitk.ac.in
*/
#include<stdio.h>
main()
{
	int i,close;
	float num[100],avg,d1,d2,sum;
	printf("\nenter the numbers :");
	sum=0;
	for(i=0;i<10;i++)	
	{
		scanf("%f",&num[i]);	//reads n numbers
		sum=sum+num[i];		//calculates sum 
	}
	avg=sum/10;		//finds the average
	close=0;
	for(i=0;i<10;i++)	//loop tp find the clossest element
	{
		if(num[i]>avg)		//calculates difference between num[i] and avg
			d1=num[i]-avg;
		else
			d1=avg-num[i];
		if(num[close]>avg)	////calculates difference between num[close] and avg
			d2=num[close]-avg;
		else
			d2=avg-num[close];

		if((d1<d2) || (d1==d2)&&(num[i]>num[close]))		//checks if num[i] is closser that num[close] to the average value
			close=i;
		
	
}
printf("\n the number clossest to the average %f is %f\n",avg,num[close]);	//prints the average and the clossest element
}